Question

F =30N 5 kg 0=50 u=0.3 A 5 kg mass is pulled along with an applied force of 30 N at 5 degrees. There is a 0.3 coefficient of friction between the mass and the floor. The mass starts from rest and moves 3.0 meters. a.) What is the weight of the mass? b.) What is the normal force on the mass? c.) What is the force of friction on the mass? d.) What is the acceleration of the mass? e.) What is the speed of the mass after it is pulled a distance of 3.0 meters if the mass starts from rest2 f.) What is the work done by the normal force? g.) What is the work done by the gravitational force? h.) What is the work done by the applied force ? 1.) What is the work done by the force of friction? j.) What is the net work? h.) Use the work-energy theorem to find the final velocity after it moves 3.0 m.

Pls help. I understand that this is a lot. I only need help from letter f through letter h. I understand the others. thank you.

Answer 1

m oficoso dl=0.3 mg well herce me 5kg I Fisino, Fi 0=50 FI=300, "=0.3. at moves 3m że s=3m. (a) we mg = 5x9.8=uare (6) R² mg-Fisino = 46.38533N. f = eeR = 13.91559832N a Ficoso - t. 3.19 405m/s2 V2-u? = pas ve 4.377704m's angle between normal forces and displacement is 9 = 40 so w = n. 3 ans cosa = 0 o=900, so w =0 also. 6 Here &=50. so wz= F cosa x S = 30 cosso x3 = 89.65753J. Herce a=180° so wy= fs cos1800 +41 7468 J. w- witw, twzt wy = 47.910737. ® w = mv p= v= 4.377 Foymis. . Please rate deat! .