V = Velocity
G = Universal Gravitational Constant
Mc = Mass of central object
R = Radius
T = Period
Mc = 5.98E+24 kg
T = 23800 s
G = 6.67428E-11 m^3/kg-s
pi = 3.14159
R^3 = [ (T^2 * G * Mc) / (4 * pi^2) ]
R^3 = { [ (23800 s)^2 * (6.67428E-11 m^3/kg-s) * (5.98E+24 kg) ] /
(4 * pi^2 ) }
R^3 = { 5.7266*10^21 m^3 }
R = 1.8*10^7 m
V = SQRT (GMc/R)
V = SQRT { [ (6.67428E-11) * (5.98E+24) ] / (1.8*10^7 m) }
V = SQRT { 22173441.33 }
V = 4708.87 m/s
Answer in m/s A satellite is in a circular orbit about the earth (M_E = 5.98...
A satellite is in a circular orbit about the earth (ME = 5.98 × 10 24 5.98 × 10 24 kg). The period of the satellite is 1.00 × 10 4 1.00 × 10 4 s. What is the speed at which the satellite travels?(G = 6.67 × 10 − 11 6.67 × 10 − 11 N.m2/kg2)
A satellite is in a circular orbit about the earth (ME = 5.98 x 1024 kg). The period of the satellite is 1.27 x 104 s. What is the speed at which the satellite travels?
A satellite is in a circular orbit about the earth (ME = 5.98 x 1024 kg). The period of the satellite is 1.07 x 104 s. What is the speed at which the satellite travels?
A spacecraft of mass m = 1900 kg is moving on a circular orbit about the earth at a constant speed v = 5.12 km/s. [Given: Mass of the earth M = 5.98 times 10^24 kg, radius of the earth R = 6.37 times10^6 m, gravitational constant G = 6.67 times 10^-11 N.m^2/kg^2.] a. Determine the radius r of the circular orbit. b. What is the period T of the orbit? c. The satellite, by firing its engines, moves to...
A satellite is in a circular orbit about the Earth at a distance of four (4) Earth radii above the surface of the Earth. What is the velocity of the satellite? (Earth's mass: ME = 5.98 x 1024 kg; the radius of the Earth: 6.4 x 106m ; G = 6.67 x 10-11 Nm2/kg2 ). A) 4,072.5 m/s B)3,530.5 m/s C)5,582.2 m/s D)7,465.9 m/s
10-3. A 639-kg satellite is in a circular orbit about Earth at a height h = 1.16 x 10^7 m above the Earth’s surface. Find (a) the gravitational force (N) acting on the satellite, (b) the satellite’s speed (m/s) (magnitude of its velocity, not its angular velocity), and (c) the period (h) of its revolution. Caution: The radius of the satellite’s orbit is not just its height above the Earth’s surface. It also includes the radius of the Earth. The...
A particular satellite was placed in a circular orbit about 163 mi above Earth. (a) Determine the orbital speed of the satellite. m/s (b) Determine the time required for one complete revolution. min 1024 kg.) An artificial satellite circling the Earth completes each orbit in 119 minutes. (The radius of the Earth is 6.38 x 106 m. The mass of the Earth is 5.98 (a) Find the altitude of the satellite. m (b) What is the value of g at...
A 544-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. m/s (b) Find the period of its revolution. (c) Find the gravitational force acting on it A satellite of Mars, called Phobos, has an orbital radius of 9.4 x 106 m and a period of 2.8 104 s. Assuming the orbit is circular, determine the mass of Mars. x 10 s. Assuming kg
1. A satellite's in a circular orbit around the earth. The period of the satellite is 25.4 hr and the radius of the orbit of the satellite is 4.39 x 107m (Mass of Earth = 5.98 x 1024 kg) What's the speed of the satellite?
6. [2pt] A satellite is in a circular orbit around the Earth. The period of the satellite is 26.7 hr. Calculate the radius of the satellite's orbit. Data: ME=5.98 x 1024 kg, G = 6.67 x 10-11 Nm²/kg2. Answer: Submit Al Answers 7. [2pt] What is the speed of the satellite in the previous problem? Answer: (Submit All Answers)