Question

Consider the cell below operating spontaneously under standard conditions at 25°C salt bridge Ag Mn2 (1M) Ag (1M) Which elect

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Mn (1) Mn 2 caps the Q Agt caq) of a ê QAg (1) E= 1.19 E= 0.60v MN (A) + 2 Agf car) - MAP (aq) + 2Ag (A) Fº= k19 +0.80 = 1.99

If you have any questions please comment

If you satisfied with the solution please rate it thanks

Add a comment
Know the answer?
Add Answer to:
Consider the cell below operating spontaneously under standard conditions at 25°C salt bridge Ag Mn2 (1M)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Part A Consider a voltaic cell that is set up as follows: Anode contains an Zn(s) electrode and 1M Zn2+(aq) Cathode cont...

    Part A Consider a voltaic cell that is set up as follows: Anode contains an Zn(s) electrode and 1M Zn2+(aq) Cathode contains a Pt(s) electrode and 1M MnO4–(aq),Mn2+(aq), and H+(aq) Which of the following statements match the cathode? Select all that apply. Group of answer choices The electrode increases in mass Oxidation occurs at this half-cell Electrons enter the half-cell The electrode is inactive Cations from the salt-bridge move to this half-cell The electrode is negative Part B Which of...

  • Since the computed value for AG is positive, the reaction is nonspontaneous under these conditions. Check...

    Since the computed value for AG is positive, the reaction is nonspontaneous under these conditions. Check Your Learning Calculate the free energy change for this same reaction at 875 °C in a 5.00 L mixture containing 0.100 mol of each gas. Is the reaction spontaneous under these conditions? ANSWER: AG +45.1 kJ/mol; no Calculating AG under Nonstandard Conditions What is the free energy change for the process shown here under the specified conditions? T 25 °C, PN, 0.870 atm, PH=0.250...

  • 2. Consider the voltaic cell illustrated below, constructed by coupling a Ni/Ni half-cell with an Ag/Ag* half-cell a...

    2. Consider the voltaic cell illustrated below, constructed by coupling a Ni/Ni half-cell with an Ag/Ag* half-cell and allowing them to react spontaneously. Refer to the table of reduction potentials and write the half-reaction that occurs at each electrode (nickel and silver). Then combine the half-reactions into the overall reaction. a. Calculate the standard cell potential. b. Annotate the diagram below. First, randomly label one electrode as Ag and one as Ni. Then identify which is the anode and which...

  • 6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e →...

    6. Consider the following galvanic cell and standard reduction potentials: Ag Pb E° = 0.80 V salt bridge Ag+ (aq) + e → Ag(s) Pb2+(aq) + 2e → Pb(s) E° = -0.13 V 1 M Ag+ 1 M Pb2+ Which one of the following statements is TRUE? a) The cell on the left containing Ag+(aq) is the anode. b) The initial reading on the voltmeter would be 0.67 V. c) Oxidation occurs in the cell on the right containing Pb²+(aq)....

  • please help wirh D E and F AG for the reaction = 13. (50) For the...

    please help wirh D E and F AG for the reaction = 13. (50) For the reaction in base. H2O2(aq) + ClO2(aq) → CO2 (aq) + O2(g) - to ges tank a. Label all parts of the voltaic cell (Parts: direction of electron flow, direction of anion/cation flow, anode, cathode, components of solutions, electrodes, salt bridge, meter) Be sure to pay attention to the gaseous component and adjust your labeling accordingly, On the lines under each half-cell, write the balanced...

  • Since the computed value for AG is positive, the reaction is nonspontaneous under these conditions. Check...

    Since the computed value for AG is positive, the reaction is nonspontaneous under these conditions. Check Your Learning Calculate the free energy change for this same reaction at 875 °C in a 5.00 L mixture containing 0.100 mol of each gas. Is the reaction spontaneous under these conditions? ANSWER: AG = +45.1 kJ/mol; no EXAMPLE 16.12 Calculating AG under Nonstandard Conditions What is the free energy change for the process shown here under the specified conditions? T = 25 °C,...

  • 26: Voltaic Cell Diagram, Cell Potential, free-energy, K Time Left:0:14:34 Rashad Reed: Attempt 1 The following...

    26: Voltaic Cell Diagram, Cell Potential, free-energy, K Time Left:0:14:34 Rashad Reed: Attempt 1 The following reaction is occurring in an voltaic cell at 25 °C Mn (s) + Br2 (1) ► Mn2+ (aq) + 2 Br(aq) The following are the standard reduction potentials: Mn2+ (aq) + 2e + Mn (5) E' = -1.18 V Br2 (1) + 2 e + 2 Br- (aq) E = 1.07 V On the paper you will submit, sketch the voltaic cell making sure...

  • The free energy change for the following reaction at 25°C, when [Ag+ - 1.16 M and...

    The free energy change for the following reaction at 25°C, when [Ag+ - 1.16 M and Cr3+1 = 9.09x10-M, is -458 kJ: 3Ag (1.16 M) + Cr(s) —+3Ag(s) + C +9.09x103) AG-458 kJ What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? Submit Answer Retry Entire Group forward 4 more group attempts rema reverse The free energy change for the following reaction at...

  • Question 7 (1 point) Calculate the standard free energy for the following reaction at standard conditions....

    Question 7 (1 point) Calculate the standard free energy for the following reaction at standard conditions. Will the galvanic cell occur spontaneously to produce potential? Cu (s) + V2+ (aq) - Cu2+ (aq) + V (s) O + 148 kJ, the reaction will not be spontaneous + 295 kJ, the reaction will not be spontaneous - 148 kJ, the reaction will occur spontaneously as written 295 kJ, the reaction will occur spontaneously as written Show Report e STRAIN605 PASSW lenovo

  • number 13 a-i please AG for the reaction - 13. (50) For the reaction in base,...

    number 13 a-i please AG for the reaction - 13. (50) For the reaction in base, H.O.(aq) + CIO.(aq) → CIO, (aq) + O2(g) to gas tank a. Label all parts of the voltaic cell (Parts: direction of electron flow, direction of anion/cation flow, anode, cathode components of solutions, electrodes, salt bridge, meter) Be sure to pay attention to the gaseous component and adjust your labeling accordingly. On the lines under each half-cell, write the balanced half-cell reaction which will...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT