Given parameters
wavelength = 300
Binding energy = 13.6 eV = 2.178 10-18 J
and we know that
speed of light C = m/s
Now kinetic energy is given by
KE = Photon Energy - Binding energy
Photon energy =
h = Planck's Constant = 6.63 10-34
= 300 = 300 10-10 meter
C = m/s
Therefore Photon Energy =
Upon calculation we get photon energy = 6.63 10-18
Therefore Kinetic Energy KE = Photon Energy - Binding energy
= 6.63 10-18 - 2.178 10-18
Kinetic Energy KE = 4.452 10-18 J
Now
m = mass of hydrogen atom = 1.67 10-27 Kg
Therefore
Upon calculation we get the velocity of the photoelectron v = 73 103 Joule/ Kg
Therefore
Kinetic Energy KE = 4.452 10-18 J
velocity of the photoelectron v = 73 103 Joule/ Kg
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