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Example 1 The voltage across the load is v(t) = 60 cos(wt - 10°) V and the current through the element in the direction of I

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Here Vet) = 60c0s (wt -60°) Lt) - lis.sin(W++-50) Vm=60 Im=1.5 A -50) A =15 (7): cos (90-ut ity - 1.5cos (wtoyo) a Here Ov=-1Rear power = Sx.cos(ov-oil = 45 cos30 4503 Re{s} =P ssincov OE Reactive power (al = 45 sinzo = us ♡ = 22:5 complex power = $

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