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BLOOD AND FLUID QUESTION 1 (0A patients blood pressure taken at the arm is 120 mmHg systolic and 70 mmHg diastolic. What wou
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Answer #1

arm bp = 120mm/70mm

height of head= 40cm ; density = 1060 Kg/m^3

pressure diiferential = 0.4 m x 9.81 m/s^2 x 1060 Kg/m^3

1Pa = 7.5 x 10^(-3) mm of Hg

pressure differential in mm = 0.4 m x 9.81 m/s^2 x 1060 Kg/m^3 *[7.5 x 10^(-3) mm of Hg]

= 31.0 mm

sistolic = 120-31.0 = 89mm

diastolic = 70mm -31 mm = 39mm

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(ii). systolic: 50 mm of Hg in A = 50 x (1000/7.5) Pa

diastolic : 25 mm of Hg in A = 25 x (1000/7.5 ) Pa

Difference in pressure = (50-25) x (1000/7.5) Pa = 0.5 x 1060 Kg/m^3 x v^2

v(A) = sqrt (25*1000/(7.5*1060*0.5)) = 2.51 m/s

v(B) = sqrt (50*1000/(7.5*1060*0.5) = 3.55 m/s

V(B) - V(A) = 1.04 m/s

(iii)

Blood flow could reduce,BP could increase

(iv)

A V = quantity per sec

0.5 x 10^(-4) m^2 x V = 0.035 L/s = 0.035 x 0.001 m^3/s

V = 0.035 x 0.001 m^3 / (0.5 x 10^(-4)) = 0.7 m/s ( rest)

Since area is becoming half while excercising , velocity will double and become 1.4 m/s(excercise)

  

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