alpha = 3
beta =2 Can you solve it in a hour please Thank you very much.
The answer is given as
alpha = 3 beta =2 Can you solve it in a hour please Thank you very...
alpha = 3 beta =2 Can you solve it in a hour please Thank you very much. 1. Consider the following initial-value problem. y' = e(1+B)t ln(1 + y2), 0<t<1 y (0) = a +1 a) ( 15p.) Determine the existence and uniqueness of the solution. b) (15p.) Use Euler's method with h = 0.25 to approximate the solution at t=0.5. {
Alpha=9 beta=3 yazarsin 3. ( 15p.) Approximate the following integral using the two-point Gaussian quadrature rule À (x + a)?e(x-1)2-3 da 4. Consider the following system.
alpha = 3 beta =2 Can you solve it in a hour please Thank you very much. 4. Consider the following system. -1 271 - I2 + 3 271 - 272 - I3 1 - 12 + 2.73 E B -2
alpha = 3 beta =2 Can you solve it in a hour please Thank you very much. 2. (20p.) Consider the cubic spline for a function f on (0,2] defined by S(z) = { (-- 1)327 ct an 10 Fritisa52 where r,c and d are constants. Find f'O) and f'(2), if it is a clamped cubic spline.
3. Approximate the following integral using the two-point Gaussian quadrature rule 2 (x + a)?e(x-1)2-Bdx
3. (15p.) Approximate the following integral using the two-point Gaussian quadrature rule | (2 + a)*e¢8–1)-+de 2 B=1 ju a=8 0
6. Compute four Legendre polynomials degree 0, 1, 2 and 3, respectively. You can assume that these polynomials endre polynomial to construct a Gaussian quadrature. Approximate the value of the integral are monic. Use the roots of the cubic Leg- sin(2x) dx using your quadrature rule. 6. Compute four Legendre polynomials degree 0, 1, 2 and 3, respectively. You can assume that these polynomials endre polynomial to construct a Gaussian quadrature. Approximate the value of the integral are monic. Use...
3. (1 point) This is 2-point Gaussian Quadrature for any f(x) dx. The weights and the nodes do not change when we integrate a new function. So...does it work? Does this actually lead to a method that is good for intergating functions in general? Use 2-point Gaussian quadrature to approximate the following integral: I e-ra da. -1 The exact value of this integral rounded to 2 decimal places is 1.49. Show your work when computing the approximation. Report the answer...
Problem 4 A definite integral I is given as .b I=| f(x) dr a=0 b=2 f(x) = e-r' ; ; ; Evaluate the integral using the three-point Gaussian quadrature method Solution: Problem 4 A definite integral I is given as .b I=| f(x) dr a=0 b=2 f(x) = e-r' ; ; ; Evaluate the integral using the three-point Gaussian quadrature method Solution:
3. Consider the function()x(x-1/2)(1) for z E 0,1]. Determine the transformed function u() introduced in the previous question. Show that | -1 u(E)dE-: 0. (Hint: you can do this without evaluating the function.) Determine the values of the midpoint rule,the simple trapezoidal rule (with two points) and of the Gaussian rule with 2 quadrature points. What do you observe about the accuracy of these rules? [10pts] 3. Consider the function()x(x-1/2)(1) for z E 0,1]. Determine the transformed function u() introduced...