Question

Consider the following Java method: public static ArrayList<Integer nums ArrayList<Integer values new ArrayList<Integer0; for(int i=10; i<30; i-i+3) if(i%) values.add(i); return values: What is returned after the method call nums()? a. [12] b. [13] c. [14] d. [15] e. [16] O

Answer 1

1)

We have a loop from i=10 to i < 30

And we're incrementing +3 every time

So, possible values of i are

10, 13, 16, 19, 22, 25, 28

We're adding i to values ArrayList if it gives 1 when we module with 5

So only 16 gives 1 when we module it with 5

So the answer is 16 which nums() method returns

2)

Initialized array with 3 elements

in the first for loop

for k=0 to k<A.length

A[k] = A.length-k;

means A[0] = 3-0 =3

A[1] = 3-1 = 2;

A[2] = 3-2 = 1;

A = [3,2,1];

In the second loop,

for k=0 to k<A.length-1

A[k+1] = A[k];

A[0+1] = A[0] = 3;

A[1+1] = A[1] = 3;

so, A = [3, 3, 3];

In the third loop we're printing array values

So the answer is 3 3 3

3)

We have arr ={1,2,3,4}

we have a loop

for k=1;k<arr.length-1;k++

arr[k] = arr[k+1]

arr[1] = arr[1+1] = 3

arr[2] = arr[2+1] = 4

arr = [1,3,4,4]

Answer is 1 3 4 4

4)

Here we have array a = {2,2,2,2}

mul = 1

In the loop we're taking each element and multiplying it with mul

So in first iteration mul = 1*2 = 2

second iteration mul = 2*2 = 4

third iteration mul = 4*2 = 8

fourth iteration mul = 8*2 =16

Answer is 16