Question

Consider the following code segment. int[]arr={1, 2, 3, 4, 5, 6, 7, 8}; for(int k=3; k<arr.length-1; R++ arr[k]-arr[k+1]; What are the contents of arr as a result of executing the code segment? a. {1, 2, 3, 5, 6, 7, 8, 8) b. {2, 2, 4, 5, 6, 7, 8, 8} C. {2, 4, 6, 5, 6, 7, 8,8} d. {4, 2, 4, 4, 6, 7, 8, 8) e. {6, 6, 4, 5, 6, 7, 8, 8}

Answer 1

1)from index 3 it will shift the values from next index to left

1,2,3,5,6,7,8,8

Option 1

2)

From  ELEMENT 2 TO Element 0 it checks if next element is greater than present and if it is It updates the previous value with adding the 1 to current index element

first iteration arr[1]>arr[2] (2>5)false

next iteration arr[2]>arr[3](5>3) true

it makes arr[1]=5+1=6

prints 2 5(k=2 arr[2]=5)

next iteration

arr[3]>arr[4](3>0) true

arr[2]=3+1=4

it prints 3 3

Next iteration is false

The final output is 2 5 3 3

Option D

3)It starts from adding 1+3=4

2+3=5

3+3=6

4+3=7

Option B

4)It multiplies each element in array

mul=1*5*2=10

Option C