Question

A construction company pays its temporary workers R100 per day if they work on a Monday to Saturday and R200 if they work on a Sunday. They only work when the company contacts them, so they do not work the whole month. Complete the program below that asks the user to enter the days that the worker has worked. The character 'l' is entered if the day is Monday to Saturday and 2’ if it is a Sunday. A total is also updated to count the number of Sundays that was worked. The program must then calculate the total amount that the worker must be paid at the end of the month. When all days have been entered, the character 'x' is entered to terminate the loop. Use an appropriate loop structure. Do not introduce any additional variables. Write down ONLY the missing statements.

Answer 1

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#include <iostream>

using namespace std;

int main()
{
char entry;
int amount=0,count=0;
while(1)
{
cout<<"\nenter the days that the worker has worked ";
cin>>entry;
if(entry=='x')
break;
if(entry=='1')
{
amount=amount+100;
}
if(entry=='2')
{
amount=amount+200;
count=count+1;
}
  
  
}
cout<<"\ntotal amount need to be paid "<<amount;
cout<<"\ncount of sunday "<<count;

return 0;
}

enter the days that the worker has worked 2 enter the days that the worker has worked 1 enter the days that the worker has worked x total amount need to be paid 300 count of sunday 1

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