I got the answer for Q1 is b)9F and Q2 is b)4F
I'm not sure if those are right answer. I hope you guys could help
me. Thank you!
r is separation between charges
When distance between triple ,it is clear that force becomes 1/9 times (F/9). So ans is (d)
When distance is doubled , force becomes one forth (=F/4). This is because force is inversely proportional to square of separation between charges. Ans is(d)
8:22 DQ 1/30: Attempt 1 Question 1 Two charges, q1 and q2 are separated by a distance r. F is the force between the two charges in this configuration. What is the new force (F) between the charges if the distance between the charges is doubled? 2) F-2F 3 F-F 4F-4F 5) F-F/4
Question 2 Two charges, q1 and q2 are separated by a distance r. F is the force between the two charges in this configuration. What is the new force (F) between the charges if the distance between the charges is halved? 1 F-F/4 3 F-F 4) F-2F 5 F-4F 0 of 2 completed Save for Later Submit
Question: Two positive charges q1 and q2 are separated by a distance r. If q1 is doubled, how will the electrostatic force between the charges charge? Please choose and explain the following: A. We need to know the charges to calculate how Fe will change. B. Fe will double C. Fe will not change D.Fe will be halved E. Fe will triple
Consider two point charges, q1 = +3x10-9 C and q2 = -2x10-9 C separated by a distance d = 6 m. (a) Find the magnitude of the electrical force (F) of interaction between the charges. (b) Find the magnitude and direction of the electric field (E) at the mid-point between charges. Answer: 1.5x10-9 N, 5 N/C (i).
Can you do A and B thank you! 6. According to Coulomb's Law, the attractive force between two electric charges of agnitude q, and q, separated by a distance r is k, where k is a constant. Let F be the net force on a charged particle P of charge Q coulombs located d centimeters above the center of a circular disk of radius R, with a uniform charge distribution of density ρ coulombs per square meter. By symmetry, F...
Q.2 - A ball, 5 m above the ground, is launched vertically downward with an initial speed vo = 4 m/s. Determine the speed of the ball at point A, just above the ground. Neglect air resistance. (VA = ?) *-*m/s oo - 22.503 m/s 45.889 m/s 10.770 m/s 1.316 m/s Q.4 - A force of kinetic friction fx = 5 N acts on a block for a distance d = 0A = 7 m. At point O, the block...
I was able to get about half way through 1 but don't know how to get to cos(cos(theta)). If I can get a step by step force each part that'd be most helpful. General Physics II, Phys 2331, Exam Prep 1) Two equal opposite charges are separated from each other with distance d create an electric dipole moment aj Find the electric potential at point A at distance r from the midpoint of two charges (see Fig 1). b) Suppose...
1-5 please Questions 1.2 T The figure above shows two particles, each with a charge of +Q, that are located at the opposite corners of a square of side d. 1. What is the direction of the net electric field at point P? (D) 1 (E) 2. What is the potential energy of a particle of charge +2q that is held at point P? (A) Zero (B) 2 kgQcc) kq (D) 2kqQ (6) 2,2 kgQ d d d d q=3.0...
Constants Two point charges, Q1-62 C and Q2 20 AC, are located between two oppositely charged parallel plates, as shown in (Figure 1). The two charges are separated by a distance of z = 048 m Assume that the electric field produced by the charged plates is uniform and equal to E- 53000 N/C. Neglect the charge redistribution in plates Part A Calculate the magnitude of the net electrostatic force on Qi Express your answer to two significant figures and...
Please answer all parts. Thank you! PART A) PART B &C) A point charge gives rise to an electric field of 3 N/C at a distance of 7 m. If the distance remains the same and the charge is increased by a factor of 5, then what will be the new electric field? N/C Submit Answer Tries 0/2 What is the magnitude of the electric field due to a point charge of -4 Q at a distance of 1 R?...