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6. According to Coulombs Law, the attractive force between two electric charges of agnitude q, and q, separated by a distance r is k, where k is a constant. Let F be the net force on a charged particle P of charge Q coulombs located d centimeters above the center of a circular disk of radius R, with a uniform charge distribution of density ρ coulombs per square meter. By symmetry, F acts in the vertical direction. Let R be a small polar rectangle of size ΔηΑθ located at distance r. Show that R exerts a force on P whose vertical component is b. Explain why Fis equal to the following double integral, and evaluate: F-kpOd Can you do A and B thank you!
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