Why is only the value of one ADC input available?
a) The interrupt occurs only at the end of the sequence.
b) There is only one data register for the ADC.
c) Data register gets over written with each conversion.
d) All of the above.
Why is only the value of one ADC input available?
a) The interrupt occurs only at...
void HAL_ADC_MspInit(ADC_HandleTypeDef* adcHandle) { GPIO_InitTypeDef GPIO_InitStruct = {0}; if(adcHandle->Instance= ADC1) { 1* USER CODE BEGIN ADC1_MspInit */ /* USER CODE END ADC1_MspInit o */ /* ADC1 clock enable */ _HAL_RCC_ADC1_CLK_ENABLE(); _HAL_RCC_GPIOA_CLK_ENABLE(); 7**ADC1 GPIO Configuration PA6 ------> ADC1_IN6 PAZ ------> ADC1_IN7 */ GPIO_InitStruct.Pin ADC1_Pin ADC2_Pin; GPIO_InitStruct.Mode - GPIO_MODE_ANALOG; GPIO_InitStruct. Pull GPIO_NOPULL; HAL_GPIO_Init(GPIOA, &GPIO_InitStruct); = = /* ADC1 DMA Init */ /* ADC1 Init */ hdma_adci. Instance = DMA2_Stream4; hdma_adc1.Init. Channel DMA_CHANNEL_0; hdma_adc1.Init.Direction DMA_PERIPH_TO_MEMORY; hdma_adc1.Init.PeriphInc DMA_PINC_DISABLE; hdma_adci. Init.MemInc = DMA_MINC_ENABLE; hdma_adci. Init.PeriphDataAlignment DMA_PDATAALIGN_HALFWORD; hdma_adc1.Init.MemDataAlignment = DMA_MDATAALIGN_HALFWORD; hdma_adci. Init.Mode = DMA_NORMAL; hdma_adc1.Init.Priority = DMA_PRIORITY_LOW; hdma_adc1. Init. FIFOMode DMA_FIFOMODE_DISABLE; if (HAL_DMA_Init(&hdma_adc1) != HAL_OK) Error_Handler(); } HAL_LINKDMA (adcHandle, DMA_Handle, hdma_adc1);/ /* ADC1 interrupt Init */ HAL_NVIC_SetPriority (ADC_IRON, 0, 0); HAL_NVIC_EnableIRQ(ADC_IRQn); /* USER CODE BEGIN ADC1_MspInit 1 */ /* USER CODE END ADC1_MspInit 1 */ } {