Question

Wavelength (nm) 275 KE (J*1019) 3.403 2.819 300 1/Wavelenth (nm-1) 0.003636364 0.003333333 0.003076923 0.002857143 0.002666667 325 2.225 350 1.83 375 1.41 400 0.0025 1.121 4 3.5 3 y=2031.8x-3.9847 R=0.9989 2.5 KE(J*1019) 2. 1.5 1 1 0.5 0 0 0.0005 0.001 0.003 0.0035 0.004 0.0015 0.002 0.0025 1/Wavelength (nm-1) Slope = 2031.8 J*1019 / nm-1 = 2031.8*10-19 J nm = 2031.8*10-19*10-9 J m = 2031.8*10-28 Jm
Based on this information, how can I calculate (a) the work function (phi), (b) the value of Planck's constant and (c) the maximum wavelength, in nm, for the photoelectric effect to manifest?

Answer 1

Salo E W + KE(max) W + KEmas he C KE max= y, ſ = x) KE max= [-W) + he y= heat (-W) y = 2031.84+13.9847)

00) So. work function 3.9947 Jx lots A 3,9847%2019 @ 19 (b) hc - 20 31.8 x -28 2031.8.x to J hm Jm. -34 he 2031.8 x do -28 3x108 отxty (C) maine ไม่ - hc Aman F dman ha W dmar zorgtoppogotovo 34 6.67x do 3.8847x lo *3x12 nan = Amana 5:022x107 meter wyt ros