Question

1 Normal 1 No Spac... Heading 1 + x, x² AO-A- -- AL Paragraph Styles Font TOR Consider the reaction and predict the net reaction shift with the changes to the system: CyHa (g) + Cl2 (g) = C2H4Cl2(g) AH = -89.5 kJ/mol a. The volume is increased in the system b. The temperature is decreased in the system C. Cl2 is added to the system d. C2H4Cl2 is removed from the system e. The pressure is increased on the system. f. A catalyst is added to the system. 0.820 moles of NO were placed in a 2.5L reaction vessel. The equilibrium constant for this reaction is 2.60 x 109. What are the equilibrium concentrations for NO, N2, and O2? 2NO(g) → N2(g) +O2 (8)

Answer 1

C2H4(g) + Cl2(g) ----------> C2H4Cl2(g) $\Delta$ H = -89.5Kj/mole

a. The volume is increased in the system the equilibrium shift to right side

b. The temperature is decreased in the system the equilibrium shift to right side

c. Cl2 is added to system the equilibrium shift to right side

d. C2H4Cl2 is removed from the system the equilibrium shift to right side

e. The pressure is increased on the system the equilibrium shift to right side

f. A catalyst is added to the system no change the equilibrium

part-B

molarity of NO = no of moles/volume in L

= 0.82/2.5 = 0.328M

--------------- 2NO(g) ---------------> N2(g) + O2(g)

I ------------- 0.328 ---------------------0 ---------- 0

C----------- -2x ----------------------- +x --------- +x

E---------- 0.328-2x ------------------ +x ---------- +x

Kc = [N2][O2]/[NO]^2

2.6*10^-3 = x*x/(0.328-2x)^2

2.6*10^-3(0.328-2x)^2 = x^2

x = 0.015

[NO] = 0.328-2x = 0.328-2*0.015 = 0.298M

[N2] = x = 0.015M

[O2] = x = 0.015M