help please. It's all one problem.
Let, (6,9π) = (r,A) ; A is angle.
Then in Cartesian coordinate
x = rcosA= 6cos9π = -6 &
y = rsin9π= 6sin9π = 0
As (-6,0) point lie on negative x-axis
So, 4th option graph is correct graph
Now , x = 6cos9π = -6cos(0) or, 6cos(-π) or, 6cos(π)
And, y = 6sin9π = -6sin(0) or, 6sin(-π) or, 6sin(π)
Hence, (r, theta)= (-6,0)
(r,theta) = (6 , -π)
(r,theta) = (6 , π)
help please. It's all one problem. Plot the point given in polar coordinates. (6,97) TT 2...
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