Question

Express the complex number 6i in polar form, z=r⁢ei⁢θ. Use a value for θ with 0≤θ<2π.

r = ?

Answer 1

Let, z= 6i

$\mathrm{\;z= 6(0+i)}$
$\mathrm{\;z= 6(\cos\frac{\pi}{2}+i\sin\frac{\pi}{2})}$
$\mathrm{\;z= 6e^{i\frac{\pi}{2}}} \;\;\;\;\;\;\;\;::\mathrm{ {\color{Blue} e^{i\theta} = (\cos\theta+i\sin\theta)}}$
Please comment if you have any doubt in the solution, I will be happy to help you!
Happy Learning!!!!!!!