Solution:
The values provided in the questions are sec(β)*tan(β) /csc(β)
let
= sec(β)*tan(β) /csc(β) ----------------------------->1
we know that formula
substitute the formula 1/csc(β) = sin(β) , sec(β) = 1/cos(β) , sin(β) /cos(β) = tan(β) into equation 1
= sin(β)*tan(β) / cos(β)
= tan(β)*tan(β)
= tan2(β)
1st option
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