Question

Write the following expression as a single trigonometric function or a power of a trigonometric function. sec B tanp CSCB Cho
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Answer #1

Solution:

The values provided in the questions are sec(β)*tan(β) /csc(β)

let

= sec(β)*tan(β) /csc(β) ----------------------------->1

we know that formula

substitute the formula 1/csc(β) = sin(β) , sec(β) = 1/cos(β) , sin(β) /cos(β) = tan(β) into equation 1

= sin(β)*tan(β) / cos(β)

= tan(β)*tan(β)

= tan2(β)

1st option

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