Question

Gauss’s law for electricity gave us a value for the electric field a distance r away...

Gauss’s law for electricity gave us a value for the electric field a distance r away (E = (1/4πε0)(qenclosed/r2). You have a conductive solid sphere (radius of a) inside a conductive shell (inner radius of b and outer radius of c). The sphere has a charge of +4Q while the shell has a charge of +10Q. Find the following: a. What is the electric field for r<a? What is the electric field for b>r>a? b. What is the net charge on the INNER SURFACE OF THE SHELL?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution. Gaussian Surface +40 +100 For esa using Gause law Take a Gaussian Surface, the change endlosed surface is zero for

Add a comment
Know the answer?
Add Answer to:
Gauss’s law for electricity gave us a value for the electric field a distance r away...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2. (10 points) In class we found the Gauss's law for electricity gave us a value...

    2. (10 points) In class we found the Gauss's law for electricity gave us a value for the electric field a distance r away (E = (1/41ɛo) (Aenclosed/r?). You have a conductive solid sphere (radius of a) inside a conductive shell (inner radius of b and outer radius of c). The sphere has a charge of +4Q while the shell has a charge of +10Q. Find the following: a. What is the electric field for r<a? What is the electric...

  • 2. (10 points) in class we found the Gauss's law for electricity gave us a value...

    2. (10 points) in class we found the Gauss's law for electricity gave us a value for the electric field a distance r away (E = (1/4xxo) (encloud/r"). You have a conductive solid sphere (radius of a) inside a conductive shell (inner radius of b and outer radius of c). The sphere has a charge of +4Q while the shell has a charge of +100. Find the following: What is the electric field for ra? What is the electric field...

  • Use Gauss’s law to calculate the electric field at a distance r from a point charge...

    Use Gauss’s law to calculate the electric field at a distance r from a point charge +q. Hints: (1) If you use a spherical shell of radius r as your closed surface, then by symmetry the magnitude of the electric field is the same at all points on the sphere, and thus E can be factored out of the integral. (2) Since 4 r^2 is the equation for the area of the surface of a sphere, ´ dA = 4...

  • A smooth spherical shell of electricity insulating material with outer radius a and inner radius a/2....

    A smooth spherical shell of electricity insulating material with outer radius a and inner radius a/2. Inside of this sphere, also with a radius of a/2, is a conducting solid sphere. The conducting sphere has an excess amount of charge q. The density of the insulating sphere is p. A) What must be the value of p so that the total charge of this setup is 0? B) Using the value of p from part (A), what are the magnitude...

  • 1. Find the electric field at point a for: a. A solid sphere of radius R...

    1. Find the electric field at point a for: a. A solid sphere of radius R carrying a volume charge density ρ b. An infinitely long, thin wire carrying a line charge density Side Cross Section C. A plane of infinite area carrying a surface charge density ơ PoT 2. Avery long cylinder with radius a and charge density pa-is placed inside of a conducting cylindrical shell. The cylindrical shell has an inner radius of b and a thickness of...

  • In the figure the sphere of radius R is solid and non-conductive and has a uniform...

    In the figure the sphere of radius R is solid and non-conductive and has a uniform charge volumetric distribution p0. A spherical shell with inner radius 2R and outer radius 3R is concentric with the sphere and unloaded. Find, in terms of p0 and R: a) the value of the electric charge in the sphere, b) the magnitude of the electric field at a radial distance r - 2.5R, c) the value of the surface charge density induced in the...

  • Please show work for all parts, thank you. Course Contents> ... > Assignment #3: Gauss' Law...

    Please show work for all parts, thank you. Course Contents> ... > Assignment #3: Gauss' Law » 23-49 Electric field of a solid sphere concentric with a < Timer Notes Evaluate Feedback Print Info In the figure, a solid sphere of radius a = 8.6 cm is concentric with a spherical conducting shell of inner radius b = 20.6 cm and outer radius c = 22.6 cm. The sphere has a net uniform charge 41 = 6.00x10- C. The shell...

  • Consider a charged sphere of radius R. The charge density is not constant. Rather, it blows...

    Consider a charged sphere of radius R. The charge density is not constant. Rather, it blows up at the center of the sphere, but falls away exponentially fast away from the center, p(r)=(C/r2)e-kr where C is an unkown constant, and k determines how fast the charge density falls off. The total charge on the sphere is Q. a) Write down the Electric Field outside the sphere, where r ≥ R, in term of the total Q. b) Show that C=...

  • 1. A very long, uniformly charged cylinder has radius R and charge density p. Determine the...

    1. A very long, uniformly charged cylinder has radius R and charge density \rho. Determine the electric field of this cylinder inside (r<R) and outside (r>R)2. A large, flat, nonconducting surface carries a uniform surface charge density σ. A small circular hole of radius R has been cut in the middle of the sheet. Determine the electric field at a distance z directly above the center of the hole.3. You have a solid, nonconducting sphere that is inside of, and...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT