Question

The force exerted by a uniform magnetic field on an electron is 1.7 N while the...

The force exerted by a uniform magnetic field on an electron is 1.7 N while the electron moves at a constant velocity. The electron travels at 17 degrees to the direction of the field. What is the minimum possible magnitude of force on the electron while traveling at the same velocity in a magnetic field of the same strength? Explain.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Giveno F=1.7N Initially, Magnetic force is given by F= quB = 1.7N Now, if the electron travels at 0=170 with the feild then,

Add a comment
Know the answer?
Add Answer to:
The force exerted by a uniform magnetic field on an electron is 1.7 N while the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An electron moves with speed 5.0 times 10^5m/s in a uniform magnetic field of strength 0.60...

    An electron moves with speed 5.0 times 10^5m/s in a uniform magnetic field of strength 0.60 T that points Hast. At some instant, the electron experiences an upward magnetic force of magnitude 4.0 times 10^14 N. In what direction is the electron moving at that instant? [If there is more than one possible direction, describe all the possibilities.] On a carefully drawn and labeled diagram, show the (possible) direction(s) of the electron's velocity relative to the magnetic field and the...

  • points An electron enters a region of a uniform magnetic field with velocity V- 5.0 10...

    points An electron enters a region of a uniform magnetic field with velocity V- 5.0 10 m/s in sy direction. The magnitude of the field is 10 T and is in ydirection What is the magnetic force matitude and direction) exerted on the electron from the field? 2.4-12 N in the direction 2.4e-12 N in the ty direction 2.de-12 N in the y direction The force is zero 2.4-12 N in the direction

  • An electron moves through a region with a uniform magnetic field of unknown magnitude directed in...

    An electron moves through a region with a uniform magnetic field of unknown magnitude directed in the +y direction At the instant that the electron is moving in the +z direction with a velocity of 2.86e6 m/s, it experiences a magnetic force of 1.24 pN in the +x direction. Calculate the magnitude of the magnetic field

  • a. what is the magnitude of the force exerted on this particle by a magnetic field...

    a. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00T in the -x directon b. what is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00T in the +z direction? c. what is the magnitude of the force exerted on this particle by a magnetic field with magnitude 2.00T in the +z direction A particle with a charge of -2.15x10-8 C is moving with...

  • An electron travels at a speed of 4.0×104 m/s through a uniform magnetic field whose magnitude...

    An electron travels at a speed of 4.0×104 m/s through a uniform magnetic field whose magnitude is 1.1×10−3 T . Part A What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field are perpendicular? Express your answer using two significant figures. F F = nothing   N   SubmitRequest Answer Part B What is the magnitude of the magnetic force on the electron if its velocity and the magnetic field make an angle of...

  • An electron travels at a speed of 1.85 × 104 m/s through a uniform magnetic field...

    An electron travels at a speed of 1.85 × 104 m/s through a uniform magnetic field whose magnitude is 1.20 × 103 T. What is the magnitude of the magnetic force on the electron if its velocity vector and the magnetic field vector are perpendicular to each other?

  • PART A: An electron moves at 3.00×106 m/s through a region in which there is a...

    PART A: An electron moves at 3.00×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.50×10−2 T . A1: An electron moves at 3.00×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.50×10−2 T . A2: What is the smallest possible magnitude of the force on the electron due to the magnetic field? Express your answer in newtons to the nearest integer. A3: If...

  • An electron travels through the uniform magnetic field of field strength B = (2.5 i +...

    An electron travels through the uniform magnetic field of field strength B = (2.5 i + 3.5 j ) mT and electric field of field strength 4.00 I V/M .   If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.

  • Problem 1: An electron travels through the uniform magnetic field of field strength B = (2.5...

    Problem 1: An electron travels through the uniform magnetic field of field strength B = (2.5 i +3.5i) mt and electric field of field strength 4.00 IV/M. If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.

  • estion 10 An electron enters a region of a uniform magnetic field with velocity V =...

    estion 10 An electron enters a region of a uniform magnetic field with velocity V = 5.0-100 mis in ty direction. The magnitude of the bed 20 and any director, Westerbro and direction) exerted on the electron from the field? 2.4e-12 N in the direction 2.4e-12 N in the ty direction The force is zero 2.4e-12 N in the -y direction 2.4e-12 N in the +x direction Question 2 A mass spectrometer uses a magnetic field of 0.3 T. Singly-charged...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT