An electron moves with speed 5.0 times 10^5m/s in a uniform magnetic field of strength 0.60...
An electron moves through a region with a uniform magnetic field of unknown magnitude directed in the +y direction At the instant that the electron is moving in the +z direction with a velocity of 2.86e6 m/s, it experiences a magnetic force of 1.24 pN in the +x direction. Calculate the magnitude of the magnetic field
1. Which of the following charged particles moving in a static uniform magnetic field feels no force? A. an electron with velocity opposite the direction of the magnetic field B. an electron with velocity perpendicular to the magnetic field C. a proton with velocity perpendicular to the magnetic field D. a proton with velocity making a 45 degree angle with the magnetic field 2. An electron enters a region where a uniform magnetic field points in the +z direction. If...
a) Earth's magnetic field ii) with the aid of a diagram, determine the direction of a proton as it enters Earth's magnetic field. iii) an electron is moving through a magnetic field whose magnitude is 6.5e-4T. At a certain instant, when its speed is 5.5e6 m/s , it experienced an acceleration of magnitude 0.3e15 m/s^2. Determine the angle between the electron's velocity and the magnetic field.
An electron experiences the greatest force as it travels 2.9 x106 m/s in a magnetic field when it is moving northward.The force is upward and of magnitude 7.2 x 10-13 N. What is the magnitude and direction of the magnetic field?
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 107 m/s and experiences an acceleration of 1.50 x 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. 1.11e-2 magnitude Apply the expression for the force on a charge moving through a magnetic field to find the field from the acceleration it produces. T direction - Need Help? Read It Master...
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.70 times 10^7 m/s and experiences an acceleration of 1.90 times 10^13 m/s^2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to...
An electron moves with a speed of 5.0 x 10^4 m/s perpendicular to an uniform magnetic field of 0.20 T. What is the magnitude of the magnetic force on the electron?
1. An electron moves with a speed of 1.00 x 10^5 m/s through planet Spiro’s magnetic field, which has a value of 55.0 x 10^-6 T at a particular location. When the electron moves westward, the magnetic force acting on it is directed straight upward, and when it moves northward, no magnetic force acts on it. a. What is the direction of the magnetic field? Explain your reasoning. b. What is the strength of the magnetic force when the electron...
a) A proton moves at 500 m/s in a 2 T magnetic field. What is the magnetic force experienced (magnitude and direction) if the angle between the velocity and field is: i) 0 degrees, ii) 90 degrees, iii) 45 degrees. b) An electron moving at 4.0x103 m/s in a 1.25 T magnetic field experiences a magnetic force of 1.40x10-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers.
An electron with velocity v⃗ =(3ax^+2ay^+2az^)×10^5m/s experiences zero net force at a point in the magnetic flux density B⃗ =(3ax^+7ay^+3az^)mWb/m2. Find the magnitude of the electric field E⃗ at that point. 1 point An electron with velocity U-(3a -2ay + 2a.) x 105 m/s experiences zero net force at a point in the magnetic flux density B mWb/m2. Find the magnitude of the electric field E at that point. (Заг + ra, + 36) kV/m