An electron with velocity v⃗ =(3ax^+2ay^+2az^)×10^5m/s experiences zero net force at a point in the magnetic flux density B⃗ =(3ax^+7ay^+3az^)mWb/m2. Find the magnitude of the electric field E⃗ at that point.
An electron with velocity v⃗ =(3ax^+2ay^+2az^)×10^5m/s experiences zero net force at a point in the magnetic...
A proton moving in a uniform magnetic field with v⃗ 1=1.13×106ı^m/s experiences force F⃗ 1=1.70×10−16k^N. A second proton with v⃗ 2=2.06×106ȷ^m/s experiences F⃗ 2=−4.17×10−16k^N in the same field. What is the magnitude of B⃗ ? What is the direction of B⃗ ? Give your answer as an angle measured ccw from the +x-axis.
An electron moves with velocity v⃗ =(6.5i−5.2j)×10^4m/sin a magnetic field B⃗ =(−0.87i+0.65j)T. Determine the z-component of the force on the electron. I don't know why I keep getting wrong for this question. Can anyone explain how to solve this question?
An electron moves with speed 5.0 times 10^5m/s in a uniform magnetic field of strength 0.60 T that points Hast. At some instant, the electron experiences an upward magnetic force of magnitude 4.0 times 10^14 N. In what direction is the electron moving at that instant? [If there is more than one possible direction, describe all the possibilities.] On a carefully drawn and labeled diagram, show the (possible) direction(s) of the electron's velocity relative to the magnetic field and the...
An electron moving at 4.5x106 m/s through a magnetic field and experiences a magnetic force of magnitude 8.4x10-13 N. If the angle between the proton's velocity and the field is 27°, find the magnitude magnetic field (in T)? (Charge and mass of an electron are 1.6x10-19 C, and 9.1x10-31 kg) 2.57 3.27 1.31 0.94
When a particle with charge q moves across a magnetic field of magnitude B, it experiences a force to the side. If the proper electric field E⃗ is simultaneously applied, the electric force on the charge will be in such a direction as to cancel the magnetic force with the result that the particle will travel in a straight line. The balancing condition provides a relationship involving the velocity v⃗ of the particle. In this problem you will figure out how to...
An electron experiences the greatest force as it travels 2.9 x106 m/s in a magnetic field when it is moving northward.The force is upward and of magnitude 7.2 x 10-13 N. What is the magnitude and direction of the magnetic field?
An electron moving at 4.15 x 103 m/s in a 1.05 T magnetic field experiences a magnetic force of 1.35 x 10-16N. What angle (in degrees, between 0 and 90°) does the velocity of the electron make with the magnetic field?
An electron moving at 3.88x10^3 m/s in 1.23T magnetic field experiences a magnetic force of 1.40x10^-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0 and 180. Smaller value: Larger value :
A proton, traveling with a velocity of 6.7 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.3 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero.
A proton, traveling with a velocity of 3.9 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 8.3 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero.