An electron moves with velocity v⃗ =(6.5i−5.2j)×10^4m/sin a magnetic field B⃗ =(−0.87i+0.65j)T.
Determine the z-component of the force on the electron.
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An electron moves with velocity v⃗ =(6.5i−5.2j)×10^4m/sin a magnetic field B⃗ =(−0.87i+0.65j)T. Determine the z-component of...
An electron moves with velocity v ⃗ =(6.8i−5.3j)× 10 4 m/s in a magnetic field B ⃗ =(−0.64i+0.57j)T . Part A Determine the x-component of the force on the electron. Express your answer using two significant figures. Fx = N Part B Determine the y-component of the force on the electron. Express your answer using two significant figures. Fy = N Part C Determine the z-component of the force on the electron. Express your answer using two significant figures....
A particle with charge − 5.40 nC is moving in a uniform magnetic field B⃗ =−( 1.28 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^. Part A Part complete Are there components of the velocity that are not determined by the measurement of the force? Are there components of the velocity that are not determined by the measurement of the force? yes no SubmitPrevious Answers Correct Part B...
An electron with velocity v⃗ =(3ax^+2ay^+2az^)×10^5m/s
experiences zero net force at a point in the magnetic flux density
B⃗ =(3ax^+7ay^+3az^)mWb/m2. Find the magnitude of the electric
field E⃗ at that point.
1 point An electron with velocity U-(3a -2ay + 2a.) x 105 m/s experiences zero net force at a point in the magnetic flux density B mWb/m2. Find the magnitude of the electric field E at that point. (Заг + ra, + 36) kV/m
A proton moves in the magnetic field B⃗ =0.56i^T with a speed of
9.0×106 m/s in the directions shown in the figure. (Figure 1)
Part B
In Figure (b), what is the magnetic force
F⃗ on the proton? Give your answers in
component form.
Express vector F⃗
in the form of
Fx,
Fy,
Fz , where the
x,
y, and
z components are separated by
commas.
An electron with velocity v = (12 m/s) i moves through a magnetic field B = (4.0 T) k. (i, j, and k denote unit vectors pointing along the x, y, and z axes, respectively.) Find the direction of the force on the electron.
The magnetic field inside a solenoid of circular cross section is given by B⃗ =btk^, where b = 3.0 T/ms . At time t = 0.32 μs , a proton is inside the solenoid at x = 5.6 cm , y= z=0 , and is moving with velocity v⃗ = 5.0 j^Mm/s . Part A Find the electromagnetic force on the proton. Express your answers using two significant figures separated by commas.
An electron moves with velocity 7 =(7.91 – 7.0) x 104ms a magnetic field B=(-0.75i +0.633) T Part A Determine the x-component of the force on the electron. Express your answer using two significant figures. 190 A * O O ? Submit Request Answer Part B Determine the y-component of the force on the electron. Express your answer using two significant figures. % ALDO ? Fy= N Submit Request Answer Part Determine the 2-component of the force on the electron...
An electron moves in the magnetic field B? = 0.510 i^T with a
speed of 1.10 ×107m/s in the directions shown in the figure. For
each, what is magnetic force F? on the electron? (Figure 1)
Question 8 An electron moves in the magnetic field B 0.510 i T with a speed of 1.10 x107 m/s in the directions shown in the figure. For each, what is magnetic force Fon the electron? (Figure 1) You may want to review (DA...
An electron that has velocity = (7.10×106m/s) for the x component and + (1.83×106m/s) for the y component moves through the uniform magnetic field = (1.950 T) x component and - (1.930 T) y component. Find the magnitude of the force on the electron due to the magnetic field. Repeat your calculation for a proton with the same velocity and magnetic field.
An electron that has a velocity with x component 2.7 × 106 m/s and y component 2.3 × 106 m/s moves through a uniform magnetic field with x component 0.033 T and y component -0.21 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.