Question

An electron experiences the greatest force as it travels 2.9 x10⁶ m/s in a magnetic field when it is moving northward.The force is upward and of magnitude 7.2 x 10^-13 N. What is the magnitude and direction of the magnetic field?

Answer 1

       magnitude of magnetic field B =F/(qV)
                                                   = (7.2 x 10^-13 N)/[(1.6*10^-19C)(2.9 x10⁶ m/s)]

                                                   = 1.55 T   
         From right hand rulethe direction of the magnetic field is toward East.

       Hope this helps you.