The magnetic field and direction
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x...
A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.10 107 m/s and experiences an acceleration of 1.80 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. magnitude =
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 10^7 m/s and experiences an acceleration of 2.10 10^13 m/s2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. magnitude in T
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.70 times 10^7 m/s and experiences an acceleration of 1.90 times 10^13 m/s^2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to...
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s determine the followi (a) the radius of the circular path cm (b) the time interval required to complete one revolution An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.12 mT. If the speed of the election is 1.63 x 107 m/s...
A proton moves at a speed of 1155 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.71 T. What is the magnitude of the magnetic force on the proton?
An electron moves through a region with a uniform magnetic field of unknown magnitude directed in the +y direction At the instant that the electron is moving in the +z direction with a velocity of 2.86e6 m/s, it experiences a magnetic force of 1.24 pN in the +x direction. Calculate the magnitude of the magnetic field
A proton moves at 7.20 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.810 m. What is the field strength (in T)?
An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 2.03 mT. If the speed of the electron is 1.66 x 107 m/s, determine the following (a) the radius of the circular path cm (b) the time interval required to complete one revolution
X 107 kg) 27.25 A proton (q 1.60 x 1019 C, m 1.67 moves in a uniform magnetic field B (0.500 T)1. At t = 0 the proton has velocity components ux-1.50 × 105 m/s, vy=0, and vz = 2.00 × 105 m/s (see Example 27.4) (a) what are the magnitude and direction of the magnetic force acting on the proton? In addition to the magnetic field there is a uniform electric field in the +x-direction, E (+2.00 x 104...
A proton moving in the positive x direction with a speed of 9.1 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 1.8 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field. magnitude T