A beanbag of mass 0.2 kg is thrown with a horizontal speed of 8.3 m/s into a box of identical mass initially at rest on a flat table. The two objects undergo an inelastic collision and begin to slide across the table together, slowing down due to friction. If the box slides 1.11 meters before coming to a rest, what is the coefficient of kinetic friction between the box and table surfaces?
Dear student,
Find this solution, and RATE IT ,If you find it is helpful .your rating is very important to me.If any incorrectness ,kindly let me know I will rectify them soon.
Thanks for asking ..
A beanbag of mass 0.2 kg is thrown with a horizontal speed of 8.3 m/s into...
only need part c (20%) Problem 5: A body of mass 1.8 kg and initial speed of 39 m/s collides with an initially resting body of mass 19 kg. The bodies stick together after the collision and continue moving (in the direction of the initially moving body). The motion takes place on a horizontal flat surface with negligible friction. 33% Part (a) Find the speed of the combined body immediately after the collision, in meters per second 3.375 Correct! 33%...
1. A block of mass m = 0.23 kg slides with initial velocity v0 = 1.4 m/s along a frictionless surface (as in the figure). The block next slides through a region of length d = 0.25 m with kinetic friction. After passing through the friction region, the block slides up a curved ramp until momentarily coming to rest at a height h above the level surface. If the kinetic friction coefficient μ k = 0.204, what height h does...
09. A box of mass 1 Kg slides with initial velocity 6 m/s on a frictionless surface and collides inelastically with an identical rest box. The boxes stick together and move after the collision. What is the change of kinetic energy? A)-9 B) 18)3 D) -15]
09. A box of mass 1 Kg slides with initial velocity 6 m/s on a frictionless surface and collides inelastically with an identical rest box. The boxes stick together and move after the collision. What is the change of kinetic energy? A)-91 B)18] C)3] D) -15] E) 5
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...
A box of mass m starts sliding across a horizontal table with some initial speed. It slides distance d before coming to rest. The coefficient of kinetic friction between the table and the box is μk. Use Newton’s laws and kinematics equations to find the initial velocity of the box. Express your answer in terms of the given parameters. Solve the same problem using work and energy theorem. Do these two approaches give the same answer? What assumptions did you...
a 2 kg mass with a speed of 5 m/s approaches a 3 kg mass that is at rest. after the collision, the two masses stick together and move off together. the kinetic energy lost in this collision is....
Mass m = 0.1 kg moves to the right with speed v = 0.44 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.61 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the...
Mass m = 0.1 kg moves to the right with speed v = 0.44 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.61 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the...