A motor spins a disk (Idisk = 25.5 kgm2) with a torque of 39 Nm, and...

Question

Question

A motor spins a disk (I_disk = 25.5 kgm²) with a torque of 39 Nm, and a 18 N frictional force acts on the disk at a radius of 1.4 m. Attached to the disk at a radius of 6.6 m is a 13 kg mass. What is the magnitude of the angular acceleration in rad/s² of the system?

Answer 1

Answer #1

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f = 18 N

r = 1.4 m

m = 13 kg

R = 6.6 m

net torque = 39 - f * r + m * g * R

net torque = 39 - (18*1.4) + (13*9.8*6.6) = 854.64 Nm

net torque = I*alfa

alfa = net torque/I

alfa= 854.64/25.5

alfa= 33.515 rad/s^2

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Answer 2

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