Question 21 4 pts A0.12-kg ball is moving at - 6 m/s when it is hit...

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Answer 1

Answer #1

Given ,Initial velocity of ball, U=- 6 m/s

Final velocity of ball, V=14 m/s

Mass of the ball,M =0.12 kg

Change in momentum of the ball is

$\Delta P=$ Final momentum- initial momentum

$\Delta P=M\ast V-M\ast U$

$\Rightarrow \Delta P=M\ast(V-U)$

$\Rightarrow \Delta P=0.12\ast\left \{ 14-(-6) \right \}$

$\Rightarrow \Delta P=0.12\ast20$

$\Delta P=2.4 kg.m/s$

Answer: option (a) 2.4 kg.m/s

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Answer 2

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