Question

Con A 120-kg box resting on a horizontal surface is attached to a 5.00 kg weight by a thin, light wire that without slippage over a frictionless puley (the figure (Figure 1). The pulley has the shape of a uniform solid disk of mass 430 kg and dameter 0.540 m Part A of the surface is frictions, find the speed of the soog blocker als a distance 36 cm ΠΙΑΣ Submit Pos Best Answer * Incorrect: Try Again; 4 attempts remaining Figure 1 of 1 Part 12.0 kg of the coefficient of kinetic triction between the 12.00 kg block and the surface is 0.2 tind the speed of 5.00 kg bother als distance em VAX ? TE 5.00 kg Subm

Answer 1

Soll (A)M, 3 12 tag Iz •R=0.27 m 02 M = 4.3 kg 7 = MR2 Te g=10m/s Sky =m Us SE R.36 m 5g d after 0.36 M. let velocity al 5 kg block is w moving distance theorem energy by work Wall = OK mys = I mw² + 1 / 2 mg v² + 1 Zpwa sgas : 4502 +2 12 v2 + Į zwe اy = کیا I= MR² 7 R2 Sex 10 x 0,36 = 145N² +1 12 v ²1x4.3 v² 2 2 2 21-3 v² = 36 IN N = 1.3mis required speed

m-12 (82 M: 4.3RR: 0.27M hai T:/पार am.ga 1302 masug hd.36m 72/om2 V vi? = wil R2. let velocity of Sky energy bloch A therorem 1) By work wall m, gs - um gs. - 2 2 2 mytme+ + /7452 52 112 _2 1 = MR² RL (Sxiexe.242-66.2.12A/9X0.26) = [.svgx12v''+ 1४५.3v 21.32 18.72 v = 0.93 M. required speed
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