Question 9 20 pts An X-ray tube has an applied voltage of 88 KV. What is...

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Answer 1

Answer #1

Most energetic photon that will reach out the other end of tube will be having maximum kinetic energy of photon.

This kinetic energy is equivalent to potential energy produced.

Thus we need to first work out for gain of potential energy of photon produced by this applied potential diffrence which is given by

Δu=q Δ v

= - e × 88kv

= - 88kev

Now this potential energy is converted into kinetic energy

Thus K. E. =lΔul

=88kev

Now for most energetic x ray photon this kinetic energy is fully used up

Thus

E(max) =88kev

Thank you

Answer 2

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