Question

An object 15 cm tall is placed 80 cm in front of a converging lens with a focal length of 20 cm.

a. find the image location

b. what is the magnifications? c. what is the height of the image?

Answer 1

Concave Lens & 1 obj f=-coun ho= isunt u = - Solnit position of object fa-2ocant foral ( Concave lens object height length

@ @ we + o we know that from Lens Formula &= to t to = Itte toll (1+t +) f = -1/26 (&) = - to - which is location V=-16 lin the image م magnification ma m=y q=ho -16 & magnification = -80 m hi himlio ② (is) cm ร hi = sans height of image
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