Question

A 3.0-cm-tall object is 14 cm in front of a converging lens that has a 28 cm focal length.

Part A Calculate the image position. Part B Calculate the image height.

Answer 1

Given that object is located a distance of 14 cm, So

u = object distance = 14 cm

f = focal length of converging lens = -28 cm

Using lens equation:

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = -1/28 - 1/14

v = -3/28

v = image distance = -9.33 cm (virtual image)

Part B.

Magnification of image is given by:

M = -v/u = hi/ho

ho = height of object = 3.0 cm

So,

hi = height of image = -(v/u)*ho

hi = -(-9.33/14)*3.0

hi = 2.0 = height of image

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