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PHY <CH 05 HW Problem 5.2 In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging fr

while e that is at the sail on Part A What is the weight of the rider? Express your answer with the appropriate units. μΑ ? W

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Answer #1

Considering forces in horizontal direction,

F cos(30) = T cos(17)

F = 1700 cos(17)/cos(30)

F = 1877.22 N

Now taking vertical direction,

mg = (F/2) - T sin(theta)

Weight, W = (1877.22/2) - (1700 x sin(17))

W = 441.58 N

Comment in case any doubt please rate my answer....

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