Question

1- Below figure a rod of AB by the length of 6.0 m and mass of 20.0 kg is hinged at one end and the other end is attached to a cord and cord to the wall. A mass of 60.0 kg is at 2.0 meter from the hinge and another mass with 80 kg is at 5.0 meter from hinge. At this situation find amount of tension in cord and exerted force from wall on the hinge. string 50 • Rod wall I'm2=80kg Hinge m=boky

Answer 1

s T given that ma.abokg, r=am 12= 80kg &=sm so زه لامع)= ليه L = 6m Hog may W A the mig

FB.D Tlosso Force in x-direction T Singo B Hx= T Sinso mag 7 Foric in y- direction HY nig Hy + T Cosso A migtwing t Hy + Tlosso (6016) +200) +(80)10)= 1600 Hyt Tlosso =1600 Now Apply .t torque about point a migr, tw(1) magő (nso) (L Cos36 ) + Cossa) (Sino) » (600X9) +(300)(4) + (800)(5) = T(0) [ths: Gorzs + Gesso funzo F6 in (30+53) as izoot boot 4o00 = Boos 6T Singo s T= 5950 Singó =981.579 T= 981.58 A which is the tension in chord o

Now By 2 + T losso = 1600 F OF Hy = 1600 - I losso 16.00 -(991.58) losso Hy = 96g.os 3 Now By Hi = 7 Sinso 981058) Frisson 2 Her Hoe - Hi - 751.934 N Hrit Hy Hing Force HE = 751-73487 969.08) H = H = J+51-994)+ + 369.057 1226.565.N which is the Hing Force H = B A
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