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A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.26) at an angle of 0 = 14.8° with respect to the normal (s

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Answer #1

1) using snell's law :

ni*sin(i) = n2*sin(r)

sin(r) = sin(14.8)/1.26

sin(r) = 0.207

r1 = 11.94 degrees

2) refracted angle at bottom surface = incident angle at upper surface

So,

r2 = 14.8 degrees.

3) lateral shift = thickness*sin(i-r1) /cos(r)

D = 2*sin(2.86)/cos(11.94)

D = 0.1019 cm

4) v = c/n

v = 3*10^8/1.26

v = 2.38*10^8 m/s

5) distance travelled by light in slab :

X = 2/cos(11.94)

X = 2.044 cm

Time required = X/v

T = 2.044*10^-2/2.38*10^8

Y = 0.859*10^-10 seconds

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