Question

1. A ray of light (ray a) in air strikes a flat piece of glass at an angle of po =60.94° with respect to the normal, as shown in the figure. The index of refraction of the glass is 1.498. What is the angle 0 between the reflected ray (ray b) and refracted ray (ray c) rays? a air glass

Answer 1

Answer $\Theta$ = 83.40^o

^{solution : Three pages}

^{page 1}

^{Anun: 83.40 Rage 1 Acconding to Snell's law- Siner 0% x Sine 1 wlere angle ot epackon 0 der at ench ot e naidnt medicam erchie mediun aix X gaes 1e1 LION TLNToK = . LROX 90-f techon nidene}

^{page 2}

^{Page 2 Aue LXOR = -Ci) Thesafore, angle t octween e repleetkd vay Cray b) nd ehackd i s KOR pitinin Yhe Valves d and fom equahion ad (iii) gut we 990-9 +90-0 vaue at Calulate Me we 9 Valwe we can Calculate -60.94 Now, iven nj Since aiv hao a index ot sehmchn 1) 1.198 (ven nde ot action flan eqyaro weget poting here vawes}

^{page 3}

^{Page 3 Ix Sin 60.94 1.498xSin By 1 X Sin 6o.94 Sinor= 1498 1X0.8741 1.498 O-583 YSin (0.581) 3S.66 value ot Or in eahio Yhis pulting gct we 9=180-(9+,) 180-(60.44 + 3S.66) 180- 966 83.40 Aswer Il}