Question

An object is 22.3 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -30 cm, is 5.49 cm to the right of the first lens.

An object is 22.3 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -30 cm, is 5.49 cm to the right of the first lens. 1) Find the distance between the object and the final image formed by the second lens. 16.421 cm Submit 2) What is the overall magnification? Submit

Answer 1

for first first lend Object distance U--223 cm, focal length fa +805 cm Applying ten's formula, $+$s 1 fi sl- π 1 -22-3 dos ㅠ Ve 60154 cm ie. image due to first len & forme at distance 6.154cm to the right ist lengi of This image acts as object for lend. second

for becond less. object diftance U = (6.154-5.49) com U= 0.6 64cm. focal length f= -30 cm, Applying len's formula el- + Ő 1 f » \ + 00664 -30 → V-1.5 38cm. pl., second les & form the it 8 left pmage lo 538 um to final 1) distance between object a image 22:3+ (5.49-1.538) 26-25 cm. An B.

2). Overall ME magnification. प -6.154 - 22.3 80538 0.664 2nd leng lens

키메 M = 0.64. Ando Bign convention' - Right wards positive leftwards negative.