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In the figure, a sand grain is 3.5 cm from thin lens 1, on the central axis through the two symmetric lenses. The distance be

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La) 2 O 2.9.2 cm 3.5cm object distance focal length 4.6 cm formule have 41- . ti - V >> U - f fu fu f ut 4.6*(-3.5) -3.5 - 4.This lens 1 becomes image from the object for lens distance 50 u=-(14.64+ 9.2) object new - 23.84 cm fa = 4.6cm focal length

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