(1 point) When an ac source with a peak potential difference of 60 V is connected...

Question

Question

(1 point) When an ac source with a peak potential difference of 60 V is connected to a series RLC circuit, the peak current i

Answer 1

Answer #1

Vo=bov Peak current - Io = Vo → Z = Vo = 60 2 = 30A Z То O- 509 coso = 2/2 2 xe-xel 10 R r 32.49 2 we Rozlcos 500) = 301c0550

Answer 2

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