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2. A charge of - 3 nC and a charge of -5.8 nC are separated by a distance of 50 cm. Find the position at which a third charge
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let = -3 hc =-3x109 토 E Ea → E q 9 E 2. f 2 = -5.8hc = -5.84 10 9 separation between a and a 2 ४ - 50cm - 0.50m Ę = electricNet force on the third charge 23 = 7.5hc will be Zero where the het electric field due to q and an is zero.left of u and sight of 22 in the The direction of Ę and is same. 7 Net electric field can never be Zeso to the left of a andX of 2 dar at P Net electric field is zero ใน E 2, pa Enet E2-E = 6 > X1% Kla, x2 T -N 1 22(1) 5.8nc - 3 nc ܛܢ 7 -l 5.8 3 xl + 5.8 JO 8 7 x = 1+/5 5.8 7 soom – 20.9cm I+V 15.8 20.gom distance from a - 20.9cm distance

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