Question 4 0/2 pts Ch 13: 39a A 10 kg piece of metal displaces 2 Lof...

Question

Question

Answer 1

Answer #1

Volume of the metal = Volume of the displaced water
V = 2 L
= 2 * 10^-3 m³

Density, $\rho$ = M / V
Where M is the mass of the metal
Substituting values,
$\rho$ = 10 / (2 * 10^-3)
= 5 * 10³ kg/m³

Answer 2

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