Question

Question 4 of 7 < -75 View Policies Current Attempt in Progress In the figure, an electron with an initial kinetic energy of 4.40 keV enters region 1 at timet = 0. That region contains a uniform magnetic field directed into the page, with magnitude 0.00870 T. The electron goes through a half-circle and then exits region 1, headed toward region 2 across a gap of 23.0 cm. There is an electric potential difference AV = 2100 V across the gap, with a polarity such that the electron's speed increases uniformly as it traverses the gap. Region 2 contains a uniform magnetic field directed out of the page, with magnitude 0.0153 T. The electron goes through a half-circle and then leaves region 2. At what time t does it leave? Region 1 Region 2 OB, Number i Units s e Textbook and Media

Answer 1

The period of the electron's cercadas motion can be written as TY शाmy 2T me Thus, the total time is ( 3.), + tgap +(3), - Tme (8+$) + tgap The time spenst in the gap requires a tew steps to tiguve out, letting t = tgap thess, we want to solve, d = vot + ßat ++ (Sport) + 0.23 mm = ako me 10/6J Ko = 4.40 key = yyoo ex- f00488 x 10 me -31 9.11 X10 kg, AV = 2100V 1-60 X 10'9c, d = 0.23m, 0.23 = (3.9338 x10*)t +($.01794x104ť By sowing quadratic equation - 5.278 hs Thus, tgap 5.278ns so, the total time is (total) - Time (1 + 3 Agar ttotal = T (9.11x1031 kg) 1.60x1019c 1 0.00870T 0.0153T +5.278 ns t total 8.50314x1ogs 8.50x1095