Question

PLEASE HELP ME OUT. PLEASE HAVE WITH HANDWRITTEN AND CLEAR HANDWRITTING. PLEASE SHOW ALL YOUR WORK STEP BY STEP SOLUTION. PLEASE. I REALLY NEED CORRECT ANSWER. PLEASE DO ALL PART AS THEY HAVE ASKED TO DO.

Purpose: The purpose of this assignment is for you to demonstrate your physics problem solving skills related to the topics of Rotation of a Rigid Body. Understanding the concepts associated motion in terms of kinematics, dynamics and energy is just the beginning. We can now apply these tools to understanding some specific and practical applications. Task, to be written out by hand: 1) Read the following problem and identify the relevant physical principles and summarize them in words. 2) Draw a diagram for the object. Include all the forces, the distance from pivot point they are acting and the angle that each is being applied. 3) Write out the rotational equivalent of Newton's Second Law as it pertains to this problem. 4) Answer the questions listed below. Please do all the necessary algebra before plugging in the numerical values. Provide a final answer with the correct number of significant digits, the appropriate units and an explanation. Grading Rubric: This assignment will be graded out of a total of 20 points. Each task is worth 5 points. Problem: A 10 kg dinosaur sign is to be hung from a long thin rod. The rod is attached to the wall by a hinge at point P and has a cable at the far end attached to the wall at a height h above P. The rod is 10.0 m long and held horizontal by the cable that makes an angle with the rod of 53 degrees. It also has a mass of 4.0 kg. a) How far along the rod should the sign be fastened such that the tension in the cable is to be 125 N (relative to the wall)? b) If the cable was accidentally cut what would the angular momentum of the system be when the rod was 30 degrees below the horizontal before smashing into Caroline's Dino-Store window (model the sign as a particle)? Caroline's Dino-Store

Answer 1

This problem is from rotational motion. physical principle behind this is how force (by Dung torques on the body (rod). depending on whene force is acting matters that the body, utett or translate. one point would rotate the rigid body. produce Hinging at

2) ។ * → K늘 mg Stul-mg To Sime TCS FBD 있 bat F5 Mg FB6

3) 4 Now, equation fog rod is Inx-direction & P = Tacoso -(1) In y direction Py + Tasino = Mg + Ti Also, for Dyno fuur: 12) T = mg - 03) T → a ) Since it is in equilibrium so Et = 0 about prvot Moll + T. (Z) = I sino) u Mgl + Tix = Tha sinol (9) Now solving all equeation :- from equation (3) My L + myn Tsingl n=1 T smo smo - Mg mg 10x9.8 4x98 8.2 m twe have to put in (4) 2 2 n = lo 125] Sin 53 So, Sign should be placed at this distance.

law of Motion is applied when D the rotational Cable is cut. wa Tarque of Mg and T, is acting. from Analogous Newton's low:- T=Jq d = Angular acderation + Ti (n) = . I = Moment of Inertia て=Mat My 3 ) 4x9.86 10 + (10x9.8) (8-2) 196+ 803.6 =ggg.6 N. So, T(torque) = 99906N This is equal to, in ja 99 9.6 = Id = 4X(10) 0²) a x = 9.5 rad/s? 3 top= 0 0 = 30= I rud As, T W ? = W. 2 + 200) I rad w = 2 x 7.5X =) angular Momentum te Iw= 373.67 kg m/s wf = 2.8 rad/s 6 So