Question

Hi please help with the questions (a) and (b) AND the TASKS at the top of the page, including the rotational equivalent. I am stuck. Thank you so much : ) .

Task: 1) Identify the relevant physical principies o and summarize them in words, 2) Draw a diagram for the figure, including the forces, distance from the pivot point to and angle being applied. 3) write out the rotational equivalent of a newton's second law for this example. I INS

Answer 1

Given Data Tonsion, T=1250 Mass M = 4kg Length, IL = OM Angle o = 53° M lokg

a ) From the figure Ezo (Mgrl4) + (mg x) = T sine L & I T ( 464.840) + (10695-4) Tsina = 125 x Sin 53x10 196 +987 998.29 omg 98x = 802.29 x=8.19 Angwer from Pivot

bh, Sinzo h = 42 h2 = x + Sinzo = 14 = 10/4 = 2.5m x = 8.19/2 =4.095 m Moment of Inertia about hinge I = ML² + mx ² 3 2 Apply I= 4X10 + 10x8 192 = 804.09 kgm² Conservation of Mechanical Energy Loss in Potential Energy = Gain in Rotational kre =) Mgh, + mg ha = I² = 2 [where L = Angular Momentum = Iw] L=JC2 Mghitung hz) 1 $229-31 [(4825)+C10*4109) 3804.09 21 Ausweo 2) L = 896.55 Nus