Question

(10 points) Each red circle is a negative charge of - Q and are placed (air in between them) inside a circular conductor (blue circle) whose is charge of +2Q. Obtain the electric field between the negative and positive charge, inside and the outside of the positive charge. ОО 110 pointer

Answer 1

Gauss law:The net electric flux through the closed surface is equal to charge enclosed divided by permitivity.

Let the negative charge is present at a circle of radius R.

By induction positive charge will be induced inside the conducting shell.

so according to the convension gives 2 = I= 6-36 mA -Iz 4.545 mA = -(I, -Iz) = -1.815 A ig Sol" No charge on the surface 203729 q canducting shell. +20 charge will be present inside the conducting shell. + #2 Redrawing it :- field Electric between positive and negative charge : from therem de.ds gauss = Genclosed EXUTg2 -20 to to -20 år 47 ore

The negative charge indicate electric field will be towards the center (from positive to negative) Electric circle of negative charge and origin (center) :- field from the +20 peds = denclosed -Q - E o Shellr Electric field outside the conducting. DE.dsDenclosed to 8 .&-Q +20 to {=0 Ezo IR QA Ef of Eko The electric field is in between the shell and the circle charge negative and rest of the places having jero electrice & 0 C M field.