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Question 1 (1 point) Using the graph below, 50 ta (7) TOOTA 10 Tine (0) the displacement of the object during the first 9.0 s
Question 2 (1 point) At t = 0, a stationary police car is passed by a speeding sports car. This occurs on a straight highway.
30 posts 10 10 poliace 20 porter postcar 10 police car 10 30 090 The separation between the two cars at the 60s mark is equal
The separation between the two cars at the 60 s mark is equal to the: a) Blue area subtract the green area b) Grey area c) Bl
Question 19 (1 point) Earths mass is 5.98 x 1024 kg. Calculate the value of g at a point 4.8 x 105 km from the centre of the
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Answer #1

Sol 2. Distance covered is given by area of v-t graph. So area for police van is blue and area for speedy car is green one. So difference between their position or separtion is blue area minus green area.

Option A is correct.

Sol 19. We apply the basic gravitational acceleration formula.

8- yer xir all Me = 5.988184kg fg = grouptational force on non w fg Ghem mig Ghe g= = > Putting the values Jeft 66 67 x x 5.9

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