Homework Answers
According to law of conservation of energy, Increase in kinetic energy=Decrease in potential energy.
Now, decrease in potential energy=charge*(decrease in electric potential)=0.00775*(940-490)=3.4875 J.
So, increase in kinetic energy=3.4875 J
Hence,final kinetic energy=initial kinetic energy+increase in kinetic energy=7.5+3.4875 J=10.9875 J=11 J approximately(third option).
Add Answer to:
The electric potential at point A is + 940 V and the electric potential at point...
The electric potential at point A ls +840 V and the electric potential at point B...
The electric potential at point A ls +840 V and the electric potential at point B is +640 V . A positive point charge q = 7.50 m (millicoulombs) moves from point A to point B. The only force on the charge is the electric force. Part A - If the kinetic energy of q ls 9.60 J when it is at point A, what is its kinetic energy when it is at point B? 1.50J O 20.7J 11.1J O...
Exercise 23.12 If the electric potential at point A is +30.0 V, what is the electric...
Exercise 23.12 If the electric potential at point A is +30.0 V, what is the electric potential at point B Express your answer with the appropriate units. Constants An object with charge q-6.00109 Cis placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right, it has kinetic energy 3.00 10-7 J VValue Units Submit Reguest Answer Part B What is the...
The differences in electric potential or voltage (we use both terms interchangeably) can be used to...
The differences in electric potential or voltage (we use both terms interchangeably) can be used to determine changes in the electric potential energy of a charged object. If I have a particle with a charge q that is moving between two points in space which have a difference in electric potential (or voltage) of ΔV, the change in electric potential energy of that object is given by ΔEPE = q ΔV. When answering the following questions remember that a gain...
The differences in electric potential or voltage (we use both terms interchangeably) can be used to...
The differences in electric potential or voltage (we use both terms interchangeably) can be used to determine changes in the electric potential energy of a charged object. If I have a particle with a charge q that is moving between two points in space which have a difference in electric potential (or voltage) of ΔV, the change in electric potential energy of that object is given by ΔEPE = q ΔV. When answering the following questions remember that a gain...
A charge is moved from position A where the electric potential is 30 v to position...
A charge is moved from position A where the electric potential is 30 v to position B with electric potential 400 v. As the particle moves, its electric potential energy increases by APE=4.1x10-5 J. What is the electric charge of the particle? 9.0 MC 400 C O 110 nC 370 C 15 mc What is the electric potential energy of the electron in the figure? Both particles are fixed and can't move. Electron 3.0 nm Proton 1.2 nm O 22x10-11)
A point charge q = +39.0 µC moves from A to B separated by a distance...
A point charge q = +39.0 µC moves from A to B separated by a distance d = 0.184 m in the presence of an external electric field E with arrow of magnitude 295 N/C directed toward the right as in the following figure. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) Find the electric force exerted on...
A point charge q = +41.0 µC moves from A to B separated by a distance...
A point charge q = +41.0 µC moves from A to B separated by a distance d = 0.167 m in the presence of an external electric field E with arrow of magnitude 265 N/C directed toward the right as in the following figure. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) Find the electric force exerted on...
A particle of unknown charge obtains 0.06 J of kinetic energy when it moves from point...
A particle of unknown charge obtains 0.06 J of kinetic energy when it moves from point A to point B. Point A has an electric potential of 888.0 V and point B has an electric potential of 333.0 V. Determine the magnitude and the sign of charge. [3]
A uniform electric field of magnitude 250 V/m is directed in the positive x direction.
A uniform electric field of magnitude 250 V/m is directed in the positive x direction. A +11.0 μC charge moves from the origin to the point (x, y) = (20.0 cm, 50.0 cm). (a) What is the change in the potential energy of the charge field system? (b) Through what potential difference does the charge move?
When an alpha particle, which has charge +2e, moves from a point with an electric potential...
When an alpha particle, which has charge +2e, moves from a point with an electric potential equal to 250 V to a point with an electric potential of 1,250 V, what is the change in the electric potential energy?
The electric potential at point A ls +840 V and the electric potential at point B is +640 V . A positive point charge q = 7.50 m (millicoulombs) moves from point A to point B. The only force on the charge is the electric force. Part A - If the kinetic energy of q ls 9.60 J when it is at point A, what is its kinetic energy when it is at point B? 1.50J O 20.7J 11.1J O...
Exercise 23.12 If the electric potential at point A is +30.0 V, what is the electric potential at point B Express your answer with the appropriate units. Constants An object with charge q-6.00109 Cis placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right, it has kinetic energy 3.00 10-7 J VValue Units Submit Reguest Answer Part B What is the...
A charge is moved from position A where the electric potential is 30 v to position B with electric potential 400 v. As the particle moves, its electric potential energy increases by APE=4.1x10-5 J. What is the electric charge of the particle? 9.0 MC 400 C O 110 nC 370 C 15 mc What is the electric potential energy of the electron in the figure? Both particles are fixed and can't move. Electron 3.0 nm Proton 1.2 nm O 22x10-11)
A particle of unknown charge obtains 0.06 J of kinetic energy when it moves from point A to point B. Point A has an electric potential of 888.0 V and point B has an electric potential of 333.0 V. Determine the magnitude and the sign of charge. [3]
Most questions answered within 3 hours.
-
The charge to the left in the figure above has a
magnitude of 2.90 nC, and...
asked 50 minutes ago -
Verify the MIRR is 9.29% given cash flows in years 1 and 2 of
$1,000 each,...
asked 1 hour ago -
Calculate the pH of a 5.7 M solution of aniline (C6H5NH2; Kb =
3.8 x 10^-10)
asked 3 hours ago -
LSL R3, R3, R12
Memory
Address
Orig.
Data
Updated
Data
Register
Orig.
Data
Updated
Data
0x84F0...
asked 3 hours ago -
Air at 100 kPa and density of 1.2 kg/m3 flows upward through a
5-cm diameter inclined...
asked 3 hours ago -
Define the following concepts in your own words: (a) stiffness,
(b) strength, (c) strain,
(d) ductility,...
asked 4 hours ago -
In C++
In this homework, you will be tasked with creating functions to
manipulate strings that...
asked 5 hours ago -
An isolated colony represents a pure culture. one rare occasions
, however , a colony can...
asked 5 hours ago -
*****DO NOT ANSWER THIS QUESTION IF YOU DON'T
KNOW*******Rights and Duties of Auditors; Minimum 4000
words...
asked 6 hours ago -
The probability that Janie is wearing sunglasses is 1/4. The
probability that she is wearing sunglasses...
asked 6 hours ago -
Do you believe social media is more of a help or a hindrance in
controlling crises...
asked 7 hours ago -
Two long, parallel wires separated by 2.85 cm carry currents in
opposite directions. The current in...
asked 6 hours ago