Question

A man on a motorcycle plans to make a jump as shown in the figure. If he leaves the ramp with a speed of 31.5 m/s and has a speed of 29.3 m/s at the top of his trajectory, determine his maximum height (cin m) above the end of the ramp. Ignore friction and air resistance

Answer 1

The velocity is 38.5 m/s and the horizontal component, 36.1 m/s,

Calculate the vertical component of velocity
Vy = √(V² - Vx²)

Substitute given values

Vy = √( 31.5 )² - (29.3 ) ²)

    = 11.56 m/s

Calculate the maximum height,

H = (V·sinΘ)² / (2g)

= (Vy)² / 2g

= ( 11.56 m/s )² / 2 . 9.81 m/s²

  = 6.81 m

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