A)
HERE we have given that,
Angle = 23.5 °
Refractive index of polystyrene as,
For orange colour = 1.490
For yellow color = 1.493
So that the angle of their emergence will be,
From snells law we have,
n1Sin(theta1) = n2Sin(theta2)
So that, angle between the colors when they emerge will be,
Delta theta = 36.5363 - 35.4510
= arcSin(1.493×Sin23.5°) - arcSin(1.490Sin23.5)
Hence,
Angle = 0.08525 °
b)
And the distance for them to travell to seperation of 1mm we will have,
1/Sin36.4510- 1/Sin(36.5363) = 3.3837 m = 3.38 m
So that they have to travel
Distance = Cos36.5363) × 3.3837 = 2.718 m
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A narrow beam of light containing yellow (580 nm) and blue (470 nm) wavelengths goes from polystyrene to air, striking the surface at a 22.5° incident angle. What is the angle (in degrees) between the colors when they emerge? (b) How far would they have to travel (in m) to be separated by 1.00 mm?
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