Question

15. A lens is placed in air and then submerged in ethanol. Draw the path of light as it travels in air and in ethanol. Index of refraction nar=1, mens = 1.67 and nethanol = 1.36. Your drawing should clearly show the difference of the path of light as it travels through these two medium. Cross section of the lens surrounded by air Cross section of the lens surrounded by ethanol

Answer 1

Solution:

Given,

refractive index of air $n_{air}=1$

refractive index of lens $n_{lens}=1.67$

refractive index of ethanol$n_{ethanol}=1.36$

When light passes from air to lens it bends more and when it passes from ethanol to lens it bends less and vice-versa. The diffrerence in the refractive index is more for air-lens interface and the difference is less in case of ethanol-lens interface.

བལ་ཤ་ Air-Lens Ethanol-Lens.